The cross-section is selected not "by eye", but according to the current that will flow through the conductor. If you choose a thinner one than necessary, the insulation overheats and ages, if thicker, you pay for extra copper. Below are tables for quickly estimating the cross-section, and a formula for non-standard loads.
The current through the load is considered simple:
I = P / (U × cosφ)
Here P is power in watts, U is voltage (220 V or 380 V), cosφ is power factor. For household loads (heaters, stove, lighting) cosφ is close to 1, so for a house the formula simplifies to I = P / 220.
Example. Oven 3.5 kW: current ≈ 3500 / 220 ≈ 16 A. According to the table below, copper 2.5 mm² wire (up to 27 A) is suitable for such current with a good margin.
| Cross-sectional area, mm² | Current, A (≈) | 220 V, 1 phase, kW (≈) | 380 V, 3 phases, kW (≈) | Typical application |
|---|---|---|---|---|
| 1,5 | 19 | 4,1 | 12,5 | Lighting |
| 2,5 | 27 | 5,9 | 17,8 | Socket groups |
| 4 | 38 | 8,3 | 25,0 | Power sockets, hob |
| 6 | 46 | 10,1 | 30,3 | Apartment entrance, electric stove |
| 10 | 70 | 15,4 | 46,0 | House entrance. |
| 16 | 85 | 18,7 | 56,0 | Input, power consumers |
The power in the table is calculated at cosφ ≈ 1. For a three-phase network with 380 V, the total power is indicated for three phases.
Aluminum carries approximately a quarter less current than copper of the same cross-section, and according to modern standards, it is used from 16 mm² and above. Approximately by current rating: 16 mm² - up to 60 A, 25 mm² - up to 75 A, 35 mm² - up to 90 A, 50 mm² - up to 110 A. For household wiring, aluminum is practically not used today - copper is preferred.
Further on the topic: current load table by cross-section (open and hidden laying) and calculation of cable consumption for an apartment.
Selecting a cable of the required cross-section: VVG cable, PVC wire or all каталог.